Electronic digital logic circuitry – Multifunctional or programmable – Significant integrated structure – layout – or layout...
Reexamination Certificate
2000-07-13
2001-03-13
Tokar, Michael (Department: 2819)
Electronic digital logic circuitry
Multifunctional or programmable
Significant integrated structure, layout, or layout...
C326S037000, C326S101000, C327S564000
Reexamination Certificate
active
06201411
ABSTRACT:
FIELD OF THE INVENTION
This invention relates generally to methods and circuit configurations for providing local on-chip bypass capacitors that supply spikes of supply current to associated digital logic elements.
BACKGROUND INFORMATION
FIG. 1
(Prior Art) is a circuit diagram illustrating an integrated circuit
1
mounted on a printed circuit board. Integrated circuit
1
receives power from a voltage supply
2
via conductors
3
and
4
, VCC power terminal
5
and ground terminal
6
, and internal power and ground buses
7
and
8
. Integrated circuit
1
includes a first digital logic element
9
(an input of which is represented here as a capacitive load
10
) and a second digital logic element
11
. The second digital logic element
11
drives digital logic signals onto the input of the first digital logic element. In the illustrated example, the second digital logic element
11
is a complementary metal oxide semiconductor (CMOS) inverter
12
. Inverter
12
includes a signal input lead
13
, a P channel pullup transistor
14
, an N channel pulldown transistor
15
, and a signal output lead
16
, a supply voltage terminal
14
A, and a ground terminal
15
A.
Consider a situation in which inverter
12
switches such that a voltage on capacitive load
10
switches from a digital logic low (for example, zero volts) to a digital logic high (for example, 3.3 volts). Initially, as shown in
FIG. 2A
, the voltage Vin on the input lead
13
of inverter
12
is a digital logic high. P channel transistor
14
is therefore nonconductive and there is no current draw through P channel transistor
14
from internal power bus
7
. Because Vin is a digital logic high, N channel transistor
15
is conductive. Capacitive load
10
is therefore maintained in a discharged state by N channel transistor
15
. As shown in
FIG. 2B
, the voltage V
1
across capacitive load
10
is zero while Vin remains low.
The voltage Vin then switches from a digital logic high to a digital logic low as illustrated in
FIG. 2A. P
channel transistor
14
turns on and N channel transistor
15
turns off. With P channel transistor
14
conductive, a current I
1
flows from internal power bus
7
through P channel transistor
14
and charges capacitive load
10
. This current I
1
is illustrated in FIG.
2
C.
There is, however, a short period of time in which P channel transistor
14
is somewhat conductive before N channel transistor
15
has turned off completely. The result is a spike of current I
2
that flows from internal power bus
7
, from source to drain through P channel transistor
14
, from drain to source through N channel transistor
15
, and to internal ground bus
8
. The resulting current spike is illustrated in FIG.
2
D. The total supply current ICC
1
drawn by inverter
12
is the combination of currents I
1
and I
2
. This total supply current ICC
1
is illustrated in FIG.
2
E.
If there were no resistance or inductance between voltage supply
2
and power terminal
5
, then this spike of current could be supplied to integrated circuit
1
without dropping the voltage on VCC power terminal
5
. There is, however, a resistance and inductance associated with conductor
3
. In
FIG. 1
, this resistance and inductance is represented by resistor
17
and inductor
18
. If a spike of current were drawn across resistor
17
and inductor
18
, the result would be an undesirable dip in the voltage at VCC power terminal
5
. This undesirable dip
19
is illustrated in FIG.
2
F.
To prevent such an undesirable dip in the voltage across power and ground terminals
5
and
6
, a capacitor
20
is provided near the power and ground terminals. When the short spike of current is demanded by the integrated circuit, capacitor
20
supplies the needed spike of current thus preventing the voltage dip associated with drawing the spike of current across resistance
17
and inductance
18
. After the spike of current has been supplied and the current needs of the digital logic element
11
have subsided, the charge given up by capacitor
20
is replenished from voltage supply
2
.
The capacitance C needed is determined using the following equation:
ICC1peak
=
C
⁢
ⅆ
V
ⅆ
t
(
equ
.
⁢
1
)
The dV in this equation is the magnitude of the permissible voltage dip on internal power bus
7
. For this example, the maximum voltage dip permitted on internal power bus
7
is ten percent of the supply voltage VCC. For a VCC of 3.3 volts, dV is approximately 0.3 volts. The dt in this equation is the time duration of the current spike. In a conventional integrated circuit, an inverter switches on the order of 2 nanoseconds. The dt is therefore approximated to be 2 nanoseconds. The ICC
1
peak is the peak current drawn by a CMOS inverter in a conventional integrated circuit. This peak current ICC
1
peak can be 2 milliamperes. Accordingly, the capacitance C needed is roughly 7 picofarads (7×10
−12
F).
Dielectrics used between metal layers in conventional integrated circuits typically have had dielectric constants of about four. Metal layers have typically been separated by one micron (10
−6
meters) or more. The size of the needed capacitor if realized as a two plate capacitor is given by the following equation:
C
=
kϵ
⁢
W
·
L
H
(
equ
.
⁢
2
)
The k in the equation is the dielectric constant of the dielectric separating the capacitor plates. The &egr; in the equation is the permittivity constant 8.854×10
−12
C
2
Nm
2
. The W is the width of the capacitor plates and the L is the length of the capacitor plates. The H is the separation between the capacitor plates. As seen from the equation above, a square (W=L) capacitor of 10 pF would be about 450 microns on a side. Accordingly, the area required to realize the needed capacitor in integrated circuit form has been unrealistically large.
Off-chip discrete capacitors called “bypass capacitors” have therefore been provided on printed circuit boards along with high speed digital integrated circuits. Such a bypass capacitor is placed as close to the integrated circuit as possible so as to bridge the power and ground terminals of the integrated circuit and to supply the integrated circuit with short spikes of current when needed. Capacitor
20
is such a “bypass capacitor”.
It is herein proposed that this conventional bypass capacitor technique will be inadequate in certain high current spike situations in the future. This is because
FIG. 1
is a simplification. In reality, the internal power and ground buses
7
and
8
on the integrated circuit have significant inherent resistances and inductances.
FIG. 3
is a circuit diagram illustrating the inherent resistance
21
and inductance
22
of the internal power and ground buses
7
and
8
. If the time duration of the ICC
1
current spike is short enough and the magnitude of the ICC
1
current spike great enough, then a significant voltage drop will develop across resistance
21
and inductance
22
. As semiconductor processing technology advances and switching speeds increase, such voltage drops are anticipated to become so great that without other corrective action, voltages on internal power buses will spike below required levels and compromise circuit function. A solution is desired.
SUMMARY
Certain digital logic elements within the core of a field programmable gate array (FPGA) require relatively large spikes of supply current when they switch. One such digital logic element is an inverter in a logic block that drives a digital signal over a relatively long distance to an input lead of another digital logic element in another logic block. In one embodiment, a local bypass capacitor is provided on-chip close to the inverter in layers overlying the transistors of the inverter. When the inverter switches and draws a spike of supply current, a significant portion (greater than half) of this supply current is supplied by the local bypass capacitor. The current supplied by the local bypass capacitor reduces the size of the current spike drawn from
Cho James H.
Tokar Michael
Wallace T. Lester
Xilinx , Inc.
Young Edel M.
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