Variable-gain amplifier

Amplifiers – With semiconductor amplifying device – Including differential amplifier

Reexamination Certificate

Rate now

  [ 0.00 ] – not rated yet Voters 0   Comments 0

Details

Reexamination Certificate

active

06788144

ABSTRACT:

FIELD OF THE INVENTION
The present invention pertains to a variable-gain amplifier in which the gain is changed in accordance with the input signal.
BACKGROUND OF THE INVENTION
FIG. 5
is a schematic circuit diagram illustrating an example of a conventional variable-gain amplifier.
In
FIG. 5
, Q
1
-Q
6
represent npn transistors; R
1
-R
3
represent resistors; SC
1
and SC
2
represent constant current sinks; T
1
-T
3
and T
1
′-T
3
′ represent terminals.
The base of npn transistor Q
1
is connected to terminal T
1
, and its emitter is connected to reference potential GND via constant current sink SC
1
.
The base of npn transistor Q
2
is connected to terminal T
1
′, and its emitter is connected to reference potential GND via constant current sink SC
2
.
Resistor R
3
is connected between the emitters of npn transistor Q
1
and npn transistor Q
2
.
The emitters of npn transistor Q
3
and npn transistor Q
4
are connected together and to the collector of npn transistor Q
1
. Also, the base of npn transistor Q
3
and the base of npn transistor Q
4
are connected to terminals T
2
and T
2
′, respectively.
The emitters of npn transistor Q
5
and npn transistor Q
6
are connected together and to the collector of npn transistor Q
2
. Also, the base of npn terminal Q
5
and the base of npn transistor Q
6
are connected to terminals T
2
′ and T
2
, respectively.
The collector of npn transistor Q
3
is connected to power supply Vcc via resistor R
1
and to terminal T
3
.
The collector of npn transistor Q
6
is connected to power supply Vcc via resistor R
2
and to terminal T
3
′.
The collectors of npn transistor Q
4
and npn transistor Q
5
are directly connected to power supply Vcc.
When the variable-gain amplifier shown in
FIG. 5
with the configuration is used, the differential voltage v
1
input between terminals T
1
and T
1
′ is amplified by the gain G
1
and output as differential voltage v
3
that appears between terminals T
3
and T
3
′. The gain G
1
can vary corresponding to the differential voltage v
2
input between terminals T
2
and T
2
′.
First, the relationship between gain G
1
and differential voltage v
2
will be explained.
When the differential amplifier comprised of the transistor pair of npn transistor Q
3
and npn transistor Q
4
operates outside the saturation region, current I
1
flowing through resistor R
1
can be approximated by the following equation.
I1
=
I3
/
{
1
+
exp

(
-
v2
/
V



T
)
}
=
I3
×
A

(
v2
)
&AutoLeftMatch;
(
1
)
where
VT=kT/q
  (2)
A
(
v
2
)=1/{1+exp (−
v
2
/
VT
)}  (3)
VT in Equation (1) represents the thermal voltage of the transistor. It is expressed as shown in Equation (2) using Boltzmann's constant k, the junction temperature T of the transistor, and the charge q on the electron.
Current I
2
flowing through resistor R
2
can be approximated using the following equation similar to Equation (1).
I
2
=
I
3
′×
A
(
v
2
)  (4)
Also, when equal currents Isc flow in constant current sinks SC
1
and SC
2
, the collector current I
3
of npn transistor Q
1
and the collector current I
3
′ of npn transistor Q
2
can be approximated using the following equations.
I
3
=
Isc+Ie
  (5)
I
3
′=
Isc−Ie
  (6)
where Ie represents the current flowing through resistor R
3
.
Also, differential voltage v
1
is expressed as follows using the base-emitter voltage Vbe
1
of npn transistor Q
1
, base-emitter voltage Vbe
2
of npn transistor Q
2
, and resistance r
3
of resistor R
3
.
V
1
=
Vbe
1
r
3
×
Ie−Vbe
2
  (7)
When resistors R
1
and R
2
have the same resistance r
1
, the differential voltage v
3
is expressed as follows.
V
3
=(
I
2

I
1

r
1
  (8)
In this case, differential voltage v
1
varies by as much as &Dgr;v
1
. If the voltage change of base-emitter voltage Vbe
1
and base-emitter voltage Vbe
2
is small compared with voltage &Dgr;v
1
, voltage &Dgr;v
1
can be expressed as follows.
&Dgr;
v
1
=
r
3
×&Dgr;
Ie
  (9)
&Dgr;Ie represents the change in current Ie corresponding to the change in voltage &Dgr;v
1
.
Also, the change &Dgr;I
3
in current I
3
and the change &Dgr;I
3
′ in current I
3
′ are expressed by the following equations.
Δ



I3
=
Δ



I



e
=
Δ



v1
/
r3
&AutoLeftMatch;
(
10
)
Δ



I3

=
Δ



I



e
=
-
Δ



v1
/
r3
(
11
)
Based on Equations (10) and (11), the change &Dgr;I
1
in current I
1
and the change &Dgr;I
2
in current I
2
can be expressed as follows.
Δ



I1
=
Δ



I3
×
A

(
v2
)
=
Δ



v1
×
A

(
v2
)
/
r3
&AutoLeftMatch;
(
12
)
Δ



I2
=
Δ



I3

×
A

(
v2
)
=
-
Δ



v1
×
A

(
v2
)
/
r3
&AutoLeftMatch;
(
13
)
Based on Equations (8), (12), and (13), the change &Dgr;v
3
of differential voltage v
3
can be expressed as follows.
Δ



v3
=
(
Δ



I2
-
Δ



I1
)
×
r1
=
-
2

Δ



v1
×
A

(
v2
)
×
r1
/
r3
=
G1
×
Δ



v1
&AutoLeftMatch;
(
14
)
where
G
1
=−2
A
(
v
2

r
1
/
r
3
  (15)
Consequently, as shown in Equation 15, the gain G
1
of variable-gain amplifier
10
shown in
FIG. 5
can be changed corresponding to differential voltage v
2
.
The voltage drop Vt
3
at terminal T
3
with respect to power supply Vcc and the voltage drop Vt
3
′ at terminal T
3
′ with respect to power supply Vcc are expressed as followed on the basis of the equation.
Vt3
=
r1
×
I1
=
I



s



c
×
r1
×
A

(
v2
)
+
I



e
×
r1
×
A

(
v2
)
&AutoLeftMatch;
(
16
)
Vt3

=
r1
×
I2
=
I



s



c
×
r1
×
A

(
v2
)
-
I



e
×
r1
×
A

(
v2
)
(
17
)
In Equations (16) and (17), the second term represents a signal component that includes current Ie, which varies corresponding to the change in differential voltage v
1
, and the first term represents a certain in-phase component independent of the change in differential voltage v
1
. Also, the in-phase component varies corresponding to differential voltage v
2
. Consequently, when differential voltage v
2
is changed in order to change the gain of the variable-gain amplifier, the in-phase voltage of the output also changes correspondingly. Since there is a limit on the range of the allowable in-phase voltage in the next stage of circuit that receives differential voltage v
3
, it is necessary to limit the dynamic range of differential voltage v
3
or gain G
1
to keep the in-phase voltage within that range.
The circuit shown in
FIG. 6
is used to solve this problem of variable-gain amplifier
10
shown in FIG.
5
.
The same symbols in
FIGS. 5 and 6
represent the same respective elements. Also, in
FIG. 6
, Q
7
-Q
10
represent npn transistors, and SC
3
represents a constant current sink.
The emitters of npn transistors Q
7
-Q
10
are connected to each other and to reference potential GND via constant current sink SC
3
.
Also, the bases of npn transistor Q
7
and npn transistor Q
8
are connected to terminal T
2
, and the collectors are connected to power supply Vcc.
The base of npn transistor Q
9
is connected to terminal T
2
′, and the collector is connected to the collector of npn transistor Q
3
.
The base of npn transistor Q
10
is connected to terminal T
2
′, and the collector is connected to the collector of npn transistor Q
6
.
In the variable-gain amplifier
11
shown in
FIG. 6
, when the same current Isc as that flow

LandOfFree

Say what you really think

Search LandOfFree.com for the USA inventors and patents. Rate them and share your experience with other people.

Rating

Variable-gain amplifier does not yet have a rating. At this time, there are no reviews or comments for this patent.

If you have personal experience with Variable-gain amplifier, we encourage you to share that experience with our LandOfFree.com community. Your opinion is very important and Variable-gain amplifier will most certainly appreciate the feedback.

Rate now

     

Profile ID: LFUS-PAI-O-3248767

  Search
All data on this website is collected from public sources. Our data reflects the most accurate information available at the time of publication.