Static information storage and retrieval – Floating gate – Particular biasing
Reexamination Certificate
2001-10-29
2003-09-09
Ho, Hoai (Department: 2818)
Static information storage and retrieval
Floating gate
Particular biasing
C365S185180, C365S189050
Reexamination Certificate
active
06618289
ABSTRACT:
TECHNICAL FIELD
The invention relates to bit/column latches, and more particularly to a bit latch that can operate at a low Vcc.
BACKGROUND ART
FIGS. 1A & 1B
show a circuit diagram of a typical 64K bit EEPROM
100
(Electrically Erasable Programmable Read Only Memory) of prior art. EEPROM
100
comprises an array of memory blocks
50
. Each memory blocks
50
has 8 memory cells
1
,
2
. Each memory cell
1
,
2
has a select transistor
1
and a memory transistor
2
. Each select transistor
1
has its drain connected to a bit line
3
, its gate connected to word line
4
, and its source connected to the drain of a memory transistor
2
in the same memory cell
1
,
2
. Each memory transistor
2
has its source grounded, its drain connected to the source of a select transistor
1
in the same memory cell
1
,
2
, and its gate connected to an erase transistor
13
. There is an erase transistor
13
associated with each memory block
50
. Each erase transistor
13
has its drain connected to a control gate line
11
, its source connected to the control gates of the eight memory transistors
2
of the associated memory block
50
, and its gate connected to a word line
4
. Each bit line
3
connects, at one end, to a high voltage charge pump
16
and a bit latch
18
, and at the other end to an I/O line of data bus
8
via a Y-transistor
6
. The gate of each Y-transistor
6
is connected to a Y-decoder
9
via a Y gate line
7
. Y decoder
9
selects only one Y gate line
7
at a time. Each control gate line
11
connects, at one end, to a high voltage charge pump
22
and a bit latch
24
, and at the other end to a control gate (CG) line
12
via a Y-transistor
10
.
The programming (writing) operation of EEPROM
100
is carried out in a page mode in which 16 memory blocks
50
on a same word line
4
are programmed simultaneously. Programming cycle starts with CG line
12
being raised to Vcc (5V) and the program data intended for a memory block
50
(say, B
0
,
0
) appearing on eight lines of data bus
8
. Y decoder
9
should select the rightmost Y gate line
7
because data on data bus
8
is intended for memory block B
0
,
0
. As a result, all eight Y transistors
6
corresponding to the first row of memory blocks
50
(i.e., B
0
,
0
; B
0
,
1
; . . . ) are ON passing the data intended for memory block B
0
,
0
along eight bit lines
3
into eight bit latches
18
in FIG.
1
B.
FIG. 1B
shows only the top one of the eight bit latches
18
corresponding to the first row of memory blocks
50
.
Similarly, Y transistors
10
corresponding to the first row of memory blocks
50
(i.e., B
0
,
0
; B
0
,
1
; . . . ) are ON passing a high signal (Vcc) from CG line
12
along control gate line
11
into bit latch
24
in
FIG. 1B
corresponding to the first row of memory blocks
50
. Each of bit latches
18
and
24
comprises a pair of cross-coupled CMOS inverters and a reset transistor.
Next, the same process occurs for memory block B
1
,
0
(not shown). That is, CG line
12
is high (Vcc). Data intended for memory block B
1
,
0
appears on data bus
8
. Y decoder
9
selects the Y gate line
7
corresponding to the second row of memory blocks
50
to which memory block B
1
,
0
belongs. As a result, all eight Y transistors
6
corresponding to the second row of memory blocks
50
(i.e., B
1
,
0
; B
1
,
1
; . . . ) are ON passing the data intended for memory block B
1
,
0
along eight bit lines
3
into eight bit latches
18
(not shown) corresponding to the second row of memory blocks
50
.
Similarly, Y transistors
10
corresponding to the second row of memory blocks
50
(i.e., B
1
,
0
; B
1
,
1
; . . . ) are ON passing a high signal (Vcc) from CG line
12
along control gate line
11
into bit latch
24
(not shown) corresponding to the second row of memory blocks
50
. The same latching process occurs for other 14 rows such that data intended for 16 memory blocks B
0
,
0
; B
1
,
0
; B
2
,
0
; . . . and B
15
,
0
are stored in 128 bit latches
18
.
Next, simultaneously, all 16 high voltage charge pumps
22
corresponding to 16 rows of memory blocks
50
raise the potentials of the associated control gate lines
11
to an erasing level (20V). In the mean time, X decoder
5
selects the word line
4
corresponding to memory blocks B
0
,
0
; B
10
; B
2
,
0
; . . . ; and B
15
,
0
. As a result, all 128 memory cells
1
,
2
of the 16 memory blocks
50
are simultaneously erased.
Then, actual programming is simultaneously carried out for all 128 memory cells
1
,
2
of the 16 memory blocks B
0
,
0
; B
1
,
0
; B
2
,
0
; . . . ; and B
15
,
0
. Considering the top memory cell
1
,
2
of memory block B
0
,
0
, if its associated bit latch
18
stores a ‘high’, that is NMOS transistors
42
and PMOS transistor
48
are OFF, and NMOS transistors
46
and PMOS transistor
44
are ON, then node N
1
has a high potential (Vcc), and transistor
19
is ON. As a result, the associated high voltage charge pump
16
operates to raise node N
1
to a programming level (20V) thereby programming the top memory cell
1
,
2
of memory block B
0
,
0
.
On the other hand, if the bit latch
18
associated with the top memory cell
1
,
2
of memory block B
0
,
0
stores a ‘low’, that is NMOS transistors
42
and PMOS transistor
48
are ON, and NMOS transistors
46
and PMOS transistor
44
are OFF, then node N
1
has a low potential (0V), and transistor
19
is OFF. As a result, the associated high voltage charge pump
16
does not operate and the top memory cell
1
,
2
of memory block B
0
,
0
remains being erased. The other 127 memory cells
1
,
2
of the memory page including a first column of 16 memory blocks
50
are programmed in the same manner and at the same time.
After that, the second page including 16 memory blocks B
0
,
1
; B
1
,
1
; . . . ; and B
15
,
1
is programmed in the same manner as the first page. As the size of memory cells decreases, the operating voltage for the memory circuits also decreases. As the operating voltage is reduced below 2V, some operating problems develop. For example, assuming 1.4V and 0V represent a ‘high’ and ‘low’, respectively, on data bus
8
, then EEPROM
100
may not operate correctly. With a threshold voltage drop of 0.7V across Y transistors
6
, a ‘high’ of bit line
3
results in a voltage of 0.7V (1.4V−0.7V). This may not be high enough to switch the state of the associated bit latch
18
.
For instance, consider the bit latch
18
associated with the top memory cell
1
,
2
in
FIGS. 1A & 1B
. Initially, the bit latch
18
is reset by turning ON reset transistor
17
. As a result, bit latch
18
stores a ‘low’, meaning NMOS transistors
42
and PMOS transistor
48
are ON, and NMOS transistors
46
and PMOS transistor
44
are OFF. With only 1.4V on an I/O line
8
, it is difficult to overcome strongly conducting NMOS
42
to raise the potential of bit line
3
high enough to turn on NMOS transistor
46
so as to switch the state of bit latch
18
(making it store a ‘high’). Using a weak NMOS
42
would help make it easier to switch the state of bit latch
18
to ‘high’ but would result in bit latch
18
being unstable when bit line
3
later rises to the programming level (20V).
Therefore, it is an object of the present invention to introduce a bit latch that can be easily switched to ‘high’ but is still stable when bit line
3
later rises to the programming level (20V).
DISCLOSURE OF THE INVENTION
The present invention achieves the stated object by using a bit latch having a control transistor in series with the two transistors
44
and
42
of inverter
26
in FIG.
1
B. When a ‘high’ needs to be stored in latch
18
, the control transistor is turned on barely to weaken NMOS transistor
42
. As a result, a ‘high’ data bit on bit line
3
can more easily turn on NMOS transistor
46
of inverter
27
triggering the switch in state of bit latch
18
to ‘high’. After that, the control transistor is strongly turned on and therefore it becomes transparent to the latch. As a result, the latch is stable when the bit line later ramps up to the high prog
Kuo Harry H.
Pathak Saroj
Payne James E.
Atmel Corporation
Ho Hoai
Schneck Thomas
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