Charge pump circuit without body effects

Miscellaneous active electrical nonlinear devices – circuits – and – Specific identifiable device – circuit – or system – With specific source of supply or bias voltage

Reexamination Certificate

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Details

C327S537000, C363S059000, C363S060000

Reexamination Certificate

active

06642773

ABSTRACT:

BACKGROUND OF INVENTION
1. Field of the Invention
The present invention relates to a charge pump circuit, and more particularly, to a charge pump circuit without body effects.
2. Description of the Prior Art
Please refer to
FIG. 1
, which is a diagram of an electrical erasable and programmable read only memory (EEPROM)
10
. The EEPROM
10
has a substrate
12
, a source
14
, a drain
16
, a floating gate
18
, and a control gate
20
. There is an oxide layer
24
positioned between the floating gate
18
and a channel
22
within the substrate
12
, and the substrate
12
is electrically connected to a reference voltage Vbb. Generally speaking, the reference voltage Vbb is provided by a ground voltage (0 volts). If the EEPROM
10
is an n-channel metal-oxide semiconductor (NMOS) structure, the substrate is a p-doped region, and the source
14
and the drain
16
are both n-doped regions. On the contrary, if the EEPROM
10
is a p-channel metal-oxide semiconductor (PMOS) structure, the substrate is an n-doped region, and the source
14
and the drain
16
are both p-doped regions.
The principle of the EEPROM
10
is described as follows. A control voltage Vcg inputted to the control gate
20
will alter the number of electrons stored on the floating gate
18
. The electrons stored on the floating gate
18
further affect the threshold voltage associated with the channel
22
. Therefore, the EEPROM
10
can store two binary values according to the electrons stored on the floating gate
18
. The electrons positioned within the channels are expelled to the floating gate
18
for changing the corresponding number of electrons stored on the floating gate
18
. In order to make the drain
16
and the source
14
be electrically connected, the control voltage Vcg is applied to the control gate
20
for overwhelming the threshold voltage affected by the floating gate
18
. If the channel
22
is established successfully, a corresponding current will flow out of the drain
16
via the channel
22
. On the contrary, if the channel
22
is not established successfully, no current will exist. Therefore, the EEPROM
10
can check the establishment of the channels, that is, detect the current flowing through the source
14
and the drain
16
to determine whether a binary value “1” or an another binary value “0” is stored.
The binary value “1” or “0” is written into the EEPROM
10
through a programming process and an erasing process. For example, in order to program the EEPROM
10
, the control voltage Vcg having
10
volts is applied to the control gate
20
, a voltage Vd having 5 volts is applied to the drain
16
, and a voltage Vs having 0 volts is applied to the source
14
. When electrons move from the source
14
toward the drain
16
, an electric field formed between the control gate
20
and the source
14
and an electric field formed between the source
14
and the drain
16
will pull electrons from the channel
22
to the floating gate
18
. In order to erase the EEPROM
10
, the control voltage Vcg having −10 volts is applied to the control gate
20
, a voltage Vs having 5 volts is applied to the source
14
, and the drain
16
is floating. Because the control gate
20
has a negative voltage and the source
14
has a positive voltage, the electric field formed between the control gate
20
and the source
14
will expel electrons from the floating gate
18
to the source
14
. Therefore, the EEPROM
10
is erased with few electrons left on the floating gate
18
.
Recently, a demand for portable electric appliances has increased. Technology related to the EEPROM
10
, such as a flash memory, has been greatly researched to meet many requirements of the portable electric appliances. In order to increase the duration of using a portable electric appliance with a limited power capacity, the portable electric appliance, generally speaking, is operated under an environment providing a low operating voltage such 3.3 volts or below. As mentioned above, the programming process and erasing process individually require the control voltage Vcg with 10 volts or 10 volts inputted into the control gate
20
. Therefore, the EEPROM
10
must adopt a charge pump circuit to generate the required high voltages from the low operating voltage for executing the programming process and the erasing process.
Please refer to
FIG. 2
, which is a diagram of a driving circuit
30
of the EEPROM
10
shown in FIG.
1
. The driving circuit
30
has a memory array
32
, a clock generator
34
, a first charge pump circuit
36
for generating positive voltages, a second charge pump circuit
38
for generating negative voltages, and an address decoder
40
. The memory array
32
has a plurality of memory cells
42
arranged in a matrix format. The address decoder
40
can select one memory cell out of the memory array
32
to be further processed. The driving circuit
30
uses the operating voltage Vdd provided by a power supply
43
to work properly. If the operating voltage has a low voltage level such as 1.8 volts, the operating voltage Vdd cannot be used for programming or erasing the memory cell
42
successfully. Therefore, the first charge pump circuit
36
is designed for generating a positive voltage (10 volts) required for programming the memory cell
42
, and the second charge pump
38
is designed for generating a negative voltage (−10 volts) required for erasing the memory cell
42
. In addition, in order to control operations of the first and second charge pump circuits
36
,
38
, the driving circuit
30
uses the clock generator
34
to generating a plurality of non-overlapping clock signals for driving the first and second charge pump circuits
36
correctly. The related operation is described as follows.
Please refer to
FIG. 2
,
FIG. 3
, and FIG.
4
.
FIG. 3
is a diagram of the first charge pump circuit
36
shown in
FIG. 2
, and
FIG. 4
is a timing diagram of the clock signals generated by the clock generator
34
shown in FIG.
2
. The first charge pump
36
has a plurality of transistors
44
,
46
,
48
,
50
,
52
and a plurality of capacitors
54
,
56
,
58
,
60
,
62
. The transistors
44
,
46
,
48
,
50
,
52
are all metal-oxide semiconductor (MOS) transistors. The clock generator
34
is used for generating a first clock signal
64
to the capacitors
54
,
58
and a second clock signal
66
to the capacitors
56
,
60
. Furthermore, a difference between a high voltage level and a corresponding low voltage level of the first and second clock signals
64
,
66
is equal to the operating voltage Vdd of the first charge pump circuit
36
. As shown in
FIG. 4
, the transistor
44
is turned on so that the operating voltage Vdd charges the capacitor
54
at time t
0
. Because the transistor
44
shifts the voltage transmitted through the transistor
44
by a threshold voltage Vt, the voltage of node A is Vdd−Vt. At time t
1
, the first clock signal
64
has a pulse with corresponding amplitude Vdd, and the second clock signal
66
remains at a low voltage level. Therefore, the voltage of node A becomes 2Vdd−Vt so that the transistor
46
is turned on. The voltage of node A (2Vdd−Vt) starts charging the capacitor
56
, and the voltage of node B will approach 2Vdd−2Vt. Similarly, the voltage of node C finally will approach 5Vdd−5Vt, which is greater than the operating voltage Vdd. However, substrates of the transistors
44
,
46
,
48
,
50
,
52
are commonly connected to a ground voltage (0 volts), and a voltage difference between the substrate and the source will induce a corresponding body effect. Therefore, each of the transistors
44
,
46
,
48
,
50
,
52
shift the voltage transmitted through the corresponding transistors
44
,
46
,
48
,
50
,
52
by a greater voltage difference Vt+dV. The increment dV is generated by the body effect. When the voltage levels stored by the capacitors
54
,
56
,
58
,
60
,
62
increase, the voltage difference between the substrate and the source increases. Therefore, the body effect is

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